(2x+5)(2x^2-7x+5)=0

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Solution for (2x+5)(2x^2-7x+5)=0 equation: 


Simplifying
(2x + 5)(2x2 + -7x + 5) = 0

Reorder the terms:
(5 + 2x)(2x2 + -7x + 5) = 0

Reorder the terms:
(5 + 2x)(5 + -7x + 2x2) = 0

Multiply (5 + 2x) * (5 + -7x + 2x2)
(5(5 + -7x + 2x2) + 2x * (5 + -7x + 2x2)) = 0
((5 * 5 + -7x * 5 + 2x2 * 5) + 2x * (5 + -7x + 2x2)) = 0
((25 + -35x + 10x2) + 2x * (5 + -7x + 2x2)) = 0
(25 + -35x + 10x2 + (5 * 2x + -7x * 2x + 2x2 * 2x)) = 0
(25 + -35x + 10x2 + (10x + -14x2 + 4x3)) = 0

Reorder the terms:
(25 + -35x + 10x + 10x2 + -14x2 + 4x3) = 0

Combine like terms: -35x + 10x = -25x
(25 + -25x + 10x2 + -14x2 + 4x3) = 0

Combine like terms: 10x2 + -14x2 = -4x2
(25 + -25x + -4x2 + 4x3) = 0

Solving
25 + -25x + -4x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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